Example Program:
This program uses linear search algorithm to find out a number among all other numbers entered by user.
/* Program: Linear Search Example
* Written by: Bulls Hacker from learnkro.com
* Input: Number of elements, element's values, value to be searched
* Output:Position of the number input by user among other numbers*/
class LinearSearchExample
{
public static void main(String args[])
{
int counter, num, item, array[];
//To capture user input
Scanner input = new Scanner(System.in);
System.out.println("Enter number of elements:");
num = input.nextInt();
//Creating array to store the all the numbers
array = new int[num];
System.out.println("Enter " + num + " integers");
//Loop to store each numbers in array
for (counter = 0; counter < num; counter++)
array[counter] = input.nextInt();
System.out.println("Enter the search value:");
item = input.nextInt();
for (counter = 0; counter < num; counter++)
{
if (array[counter] == item)
{
System.out.println(item+" is present at location "+(counter+1));
/*Item is found so to stop the search and to come out of the
* loop use break statement.*/
break;
}
}
if (counter == num)
System.out.println(item + " doesn't exist in array.");
}
}
Output 1:
Enter number of elements:
6
Enter 6 integers
22
33
45
1
3
99
Enter the search value:
45
45 is present at location 3
Output 2:
Enter number of elements:
4
Enter 4 integers
11
22
4
5
Enter the search value:
99
99 doesn't exist in array.
